**Use this rule when** the first bearing between the object and the bow is 2 pts (or 22.5°), and
the second bearing is 4 pts (or 45°).

__What it tells you__ is that the distance run between the two bearings will be equal to
the distance to the object when from the second position. You also know that 0.7 multiplied by the distance run is equal to
the distance to the object when abeam, and is also the distance along the track until the object will be abeam. You can also
find the ETA for when the object will be abeam by dividing 0.7xDR (in nm) by your speed (in knots), and then adding the result
to the time of the second observation.

__This works because__, as you can see in the figure at right, the triangle created when drawn out
is isoceles, meaning that two of the sides and two of the interior angles are the same. In a triangle, the sum of the three
interior angles will be 180°. If one angle is a, another is 180°-2a, and the last is b, simply solving the equation

180° = a + b + 180° - 2a will show that a = b, and therefore both angles are the same. Because both angles are the same,
the sides opposite them will be of equal length. Also, because the second triangle is a 45°-45°-90°, we can find the length
of the legs using the pythagorean theorum. Knowing the distances, we can then divide by speed to get time.